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Old 01-05-2006, 07:47 AM
Jonathan Kay [MVP]
 
Posts: n/a
Default Re: How to search for my posts?

I will e-mail people responses for $1/post
____________________________________________
Jonathan Kay
Microsoft MVP - Windows Messenger/MSN Messenger
Associate Expert
http://www.microsoft.com/windowsxp/expertzone/
Messenger Resources - http://messenger.jonathankay.com
All posts unless otherwise specified are (c) 2005 Jonathan Kay.
You *must* contact me for redistribution rights.

"Galen" <galennews@gmail.com> wrote in message news:eocc9fc0FHA.3956@TK2MSFTNGP09.phx.gbl...
> In news:73C1266A-64C7-45A8-BB53-834A3703C497@microsoft.com,
> RT <RT@discussions.microsoft.com> had this to say:
>
> My reply is at the bottom of your sent message:
>
>> There are lot of messages with the same kind of problem. So when I
>> came back and wanted to check the replies to my post (the link in the
>> auto generated mail from this website didn't work), I couldn't do
>> that.
>>
>> Is there a way to find out posts marked by me?
>>
>> Thanks,
>> RT

>
> Access MS Newsgroups :
> http://kgiii.info/windows/all/general/msnewsgroups.html
>
> Your post was answered by Mr. Kay...
>
> <quote>
>
> Hi RT,
>
> You should still have access even under a Limited User account. If you want to get
> directly
> there, click Start, then Run, type "control userpasswords2" and click OK. Then click the
> Advanced tab, and Manage Passwords.
> ____________________________________________
> Jonathan Kay
> Microsoft MVP - Windows Messenger/MSN Messenger
> Associate Expert
> http://www.microsoft.com/windowsxp/expertzone/
> Messenger Resources - http://messenger.jonathankay.com
> All posts unless otherwise specified are (c) 2005 Jonathan Kay.
> You *must* contact me for redistribution rights.
>
> </quote>
>
> --
> Galen - MS MVP - Windows (Shell/User & IE)
>
> "You know that a conjurer gets no credit when once he has explained his
> trick; and if I show you too much of my method of working, you will
> come to the conclusion that I am a very ordinary individual after all."
>
> Sherlock Holmes
>



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