A javascript error "Permission denied Error" is raised when script is
accessed from different frames. The pages in different frames are from the
same URI
It works in some of the Browsers IE6.

Permission denied error occurs for the following client side script
Environment :


<a class="QuickNavElement"
href="javascript:top._display.SetStatus()">setStat us</a> on the left frame.



This link calls a function in another frame in a different asp page



function SetStatus()

{

//Status des Fragebogens setzen

if (IsDirty(document.form1)==false)

{

X =
top._hidden2.RSExec("CheckRequiredOkay",document.f orm1.FK_Survey.value)
//?berpr?fen, ob alle Pflichfelder gef?llt

if (X.return_value==-1)

{


PreparePageChange()


top._hidden2.SetDisplayStatus()

}

else

alert("<%=LA_Mussfelder%>")

}

else

{


document.form1.SetStatus.value = -1


MySubmit(form1.FK_Block_ID.value,1)

}

}

Dependent function



function MySubmit(ps_which, ps_modus)

{







for (var i=0; i<gaAllDates.length-1; i++)

{

var elem=document.getElementById(gaAllDates[i]);

if (elem==null) continue;

//before save, we check all dates to be correct

if (!CheckDateMinMax(elem))

{

elem.focus();

return;

}

}



//Fragebogen ?berpr?fen und abschicken

if (ApproverComment == true){

top.mnmAllTopSetEnabled(false)

document.form1.NB_ID.value =
ps_which

PreparePageChange()

document.form1.submit()

return true

}



if (top._hidden2.document.form1.ms2.value == 1)

;

else

{





if (IsDirty(document.form1)==false) {


top._hidden2.document.form1.ms2.value = 0


return false

}




if
(top._hidden2.document.form1.rights.value == 1)

return false



if (CheckLoss() == false) return false

if (CheckFrequence() == false) return
false

// if (!CheckRanges()) return false //// Bug 1899
- commented Prakash Nov 09 04



top._hidden2.document.form1.ms2.value =
1

CheckMusts()

PreparePageChange()

document.all.NB_ID.value = ps_which

top._left.Loading.style.visibility =
"visible"

top._left.Loading.disabled = false

top._left.Loading.innerHTML ="Saving..."

document.form1.submit()

}

}